Will splitting RCA's drop the HU voltage output?
I saw this on another forum.... and wondered if its true. I have a Alpine CDA118 that is 10,000 ohm output impeadance at 2V, but i cannot find the input impedance anywhere for my JL amp MD750/1.
Lets take a typical Alpine HU. Lets pick this one.
CDA9856
Preout: 2 volts / 10,000 ohm output impedance..
Connect this HU to an Alpine amp with 10,000 ohm input impedance,
the voltage is now 1 volt, cut in half.
Instead of buying an Alpine amp, you found a good amp with a 47,000 ohm
input impedance, the loading effect is minimal, you get 1.95v, much better
than 1.0v when you interfaced an Alpine HU to an Alpine amp.
I was shocked years ago when I found this.
Connect two Alpine amps with splitter, you now have 0.66v.
Hint: A good HU will have a 50 ohm  200 ohm output impedance. Even 1000 ohm is ok,
but 10,000 ohm is stupid circuit design.
Moral of story: Always check equipment specs.
One HU & one amp;
HU output voltage * (amplifier input impedance / (amplifier input impedance + HU output impedance)).
Example.
HU preout voltage: 5 volts
HU output impedance: 200 ohms
Amplifier input impedance: 20,000 ohms.
5 * (20,000 / (20,000 + 200)) = 4.95 volts.
One HU & two or more amps
Step 1. Find the total parallel impedance of all your amps since the same input signal will be driving all the amp inputs.
1 / (1 / (amp#1 input impedance) + 1 / (amp#2 input impedance) + 1/ (amp#3 input impedance ... etc))
Example:
Amp #1 input impedance: 10,000 ohms
Amp #2 input impedance: 20,000 ohms
Amp #4 input impednace: 47,000 ohms
1 / (1 / (10,000) + 1 / (20,000) + 1/ (47,000)) = 5838 ohms
Step 2. Put that 5838 ohms back into the voltage divider formula.
HU output voltage * (amplifier input impedance / (amplifier input impedance + HU output impedance)).
Example.
HU preout voltage: 5 volts
HU output impedance: 200 ohms
Amplifier #1, #2, #3 parallel input impedance: 5838 ohms.
5 * (5838 / (5838 + 200)) = 4.83 volts.
Last edited by craig3972; 02102014 at 03:33 PM.
